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(x-x)^2+5=x^2-14x+54
We move all terms to the left:
(x-x)^2+5-(x^2-14x+54)=0
We add all the numbers together, and all the variables
-(x^2-14x+54)+5+0^2=0
We add all the numbers together, and all the variables
-(x^2-14x+54)+5=0
We get rid of parentheses
-x^2+14x-54+5=0
We add all the numbers together, and all the variables
-1x^2+14x-49=0
a = -1; b = 14; c = -49;
Δ = b2-4ac
Δ = 142-4·(-1)·(-49)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-14}{-2}=+7$
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